 # RD Sharma Solutions Class 10 Mathematics Solutions for Real Numbers Exercise 1.2 in Chapter 1 - Real Numbers

Two brands of chocolates are available in packs of 24 and 15 respectively. If I need to buy an equal number of chocolates of both kinds, what is the least number of boxes of each kind I would need to buy?

From the question, it’s given that

A number of chocolates of 1st brand in a pack = 24 Number of chocolates of 2nd brand in a pack = 15.

So, the least number of both brands of chocolates that need to be purchased is given by their LCM.

L.C.M. of 24 and 15 = 2 x 2 x 2 x 3 x 5 = 120

Hence, the number of packets of the 1st brand to be bought = 120 / 24 = 5

And, the number of packets of 2nd brand to be bought = 120 / 15 = 8

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