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NCERT Exemplar Solutions Class 9 Mathematics Solutions for Surface Areas and Volumes - Exercise 13.1 in Chapter 13 - Surface Areas and Volumes

Question 5 Surface Areas and Volumes - Exercise 13.1

The total surface area of a cone whose radius is r/2 and slant height 2l is

Question 5 Image - NCERT Exemplar Solutions - Mathematics - class 9 chapter Surface Areas and Volumes

Answer:

(B) πr(l+(r/4))

Explanation:

Given, radius of a cone is r/2 and slant height is 2L.

Total surface area = π × radius × slant height + π × radius2

\begin{array}{l} =\pi \times \frac{r}{2} \times 2 \times 1+\pi \times\left(\frac{r}{2}\right)^{2} \\ =\pi r l+\frac{\pi r^{2}}{4} \\ =\pi r\left(1+\frac{r}{4}\right) \end{array}

Hence, option B is the correct answer

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