Jump to
NCERT Exemplar Solutions Class 9 Mathematics Solutions for Surface Areas and Volumes - Exercise 13.1 in Chapter 13 - Surface Areas and Volumes
Question 1 Surface Areas and Volumes - Exercise 13.1
The radius of a sphere is 2r, then its volume will be
Answer:
(D) (32πr3)/3
Explanation:
Given, the radius of a sphere is 2r.
The volume of a sphere = (4/3) × (radius)3
Thus, the volume of the given sphere = (4/3) × π × (2r)3
= (4/3) × π × 8 × r3
= (32 π r3/3)
Hence, option D is the correct answer.
Related Questions
Facebook
Whatsapp
Copy Link
Exercises
Chapters
Lido
Courses
Quick Links
Terms & Policies
Terms & Policies
Connect with us on social media!
2022 © Quality Tutorials Pvt Ltd All rights reserved