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NCERT Exemplar Solutions Class 8 Mathematics Solutions for Comparing Quantities - Exercise in Chapter 9 - Comparing Quantities
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15% increase in price of an article, which is Rs.1,620, is the increase of _______ .
Answer:
Rs.212
Explanation:
Let x is the price of the article.
Thus, as per given question;
1620 = x + x × (15/100)
1620 = 115x/100
115x = 1620 × 100
x = (1620×100)/115
x = 1408
Hence, increase in price = 1620 – 1408 = 212.
Video transcript
"hello students i am rita your mass
leader tutor
and today's question is 15 increase in
price of an article which is rupees 1620
is the increase of first of all in
this question we let price of article
is equal to rupees x let
price of article is equal to
rupees x and the question according to
question
it is given that x plus
15 percent of facts is equal to
1 620 now we solve this equation
x plus 15 by 100 x is equal to 1620
now we take the lcm calcium is 100 so it
becomes 100x
plus 15x is equal to
1620 so it becomes
115 by 100x
is equal to 160 1620 so the value of
x is equal to 1620 in 200
divided by 115 so five twos are ten five
threes are fifteen five to seven zero
when we solve this equation we got the
values of
rounded off value that is one thousand
four hundred
eight but we have to find the increase
how much increase so the increase
is equal to rupees 1620
minus rupees 1408
so we got 10 minus 8 to
1 two so 212
is the answer so rupees 212
is the answer i hope you like this video
so please subscribe video for more
updates and do comment your questions
thank you
"
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