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NCERT Exemplar Solutions Class 8 Mathematics Solutions for Linear Equations in One Variable - Exercise in Chapter 4 - Linear Equations in One Variable
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4t – 3 – (3t +1) = 5t – 4
Answer:
We have,
4t – 3 – (3t +1) = 5t – 4
4t – 3 – 3t – 1 = 5t – 4
t – 4 = 5t – 4
Transposing t to RHS it becomes -t and -4 to LHS it becomes 4.
4 – 4 = 5t – t
0 = 4t
t = 0/4
t = 0
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