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NCERT Exemplar Solutions Class 8 Mathematics Solutions for Linear Equations in One Variable - Exercise in Chapter 4 - Linear Equations in One Variable

Question 58 Linear Equations in One Variable - Exercise

10x – 5 – 7x = 5x + 15 – 8

Answer:

10x – 5 – 7x = 5x + 15 – 8

3x – 5 = 5x + 7

Transposing - 5 to RHS it becomes 5 and 5x to LHS it becomes -5x.

3x – 5x = 7 + 5

  • 2x = 12

x = -12/2

x = - 6

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