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NCERT Exemplar Solutions Class 8 Mathematics Solutions for Linear Equations in One Variable - Exercise in Chapter 4 - Linear Equations in One Variable
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10x – 5 – 7x = 5x + 15 – 8
Answer:
10x – 5 – 7x = 5x + 15 – 8
3x – 5 = 5x + 7
Transposing - 5 to RHS it becomes 5 and 5x to LHS it becomes -5x.
3x – 5x = 7 + 5
- 2x = 12
x = -12/2
x = - 6
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