NCERT Exemplar Solutions Class 8 Mathematics Solutions for Linear Equations in One Variable - Exercise in Chapter 4 - Linear Equations in One Variable

Question 57 Linear Equations in One Variable - Exercise

8x – 7 – 3x = 6x – 2x – 3

Answer:

We have,

8x – 7 – 3x = 6x – 2x – 3

5x – 7 = 4x – 3

Transposing - 7 to RHS it becomes 7 and 4x to LHS it becomes -4x.

5x – 4x = 7 – 3

x = 4

Video transcript

"hello students i am rita your math leader tutor and today's question is 8x minus 7 minus 3x is equal to 6x minus 2x minus 3 first of all we solve the variables 8x minus 3x these two are the variable on our left hand side 8x minus 3x is 5x minus 7 is equal to 6x minus 2x is equal to 4x minus 3. now we separate out the variables 5x this 4x when goes to the other side by the process of transposition so it becomes minus 4x then minus 3 and minus 7 that is constants comes to the right side then it becomes plus 7 so 5 minus 4 x that is 1 x and 7 minus 3 that is 4 so the value of x is equal to 4 so this is our answer i hope you like this video so please subscribe video for more updates and do comment your questions thank you"

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Exercises

Linear Equations in One Variable - Exercise

Chapters

Rational Numbers

Data Handling