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NCERT Exemplar Solutions Class 8 Mathematics Solutions for Linear Equations in One Variable - Exercise in Chapter 4 - Linear Equations in One Variable
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0.4(3x –1) = 0.5x + 1
Answer:
We have,
0.4(3x –1) = 0.5x + 1
1.2x – 0.4 = 0.5x + 1
Transposing - 0.4 to RHS it becomes 0.4 and 0.5x to LHS it becomes -0.5x.
1.2x – 0.5x = 1 + 0.4
0.7x = 1.4
x = 1.4/0.7
x = 14/7
x = 2
Video transcript
"hello students i am data your mass
leader tutor
and the today's question is 0.4 bracket
3x minus 1 bracket close is equal to
0.5 x plus 1
so first of all we apply distributive
property 0.4
multiply 3x minus
0.4 multiply 1
is equal to 0.5 x
plus 1 0.4 into
3 it becomes 1.2 x
minus 0.4 is equal to
0.5 x plus 1 now we separate out the
variables there are two variables 1.2 x
and 0.5 x
so 1.2 x when 0.5 go to the other side
by the process of
transposition then it becomes minus 0.5
x now 1 minus 0.4 when it goes to the
right side then it becomes
plus 0.4 now we solve this
1.2 minus 0.5 then it becomes
0.7 and 1 plus 0.4 then it becomes
1.4 now the value of x 1.4
divided by 0.7 okay
so when we remove that point
then we multiply by 10
because we remove the decimal from 7
and again in denominator we multiply by
10 also so 10 10 cancel out by
each other 7 and 7 2
so the value of x is equal to 2
so this is our answer i hope you like
this video so please subscribe leto for
more updates and do comment your
questions thank you"
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