# NCERT Exemplar Solutions Class 8 Mathematics Solutions for Linear Equations in One Variable - Exercise in Chapter 4 - Linear Equations in One Variable

Question 56 Linear Equations in One Variable - Exercise

0.4(3x –1) = 0.5x + 1

We have,

0.4(3x –1) = 0.5x + 1

1.2x – 0.4 = 0.5x + 1

Transposing - 0.4 to RHS it becomes 0.4 and 0.5x to LHS it becomes -0.5x.

1.2x – 0.5x = 1 + 0.4

0.7x = 1.4

x = 1.4/0.7

x = 14/7

x = 2

Video transcript
"hello students i am data your mass leader tutor and the today's question is 0.4 bracket 3x minus 1 bracket close is equal to 0.5 x plus 1 so first of all we apply distributive property 0.4 multiply 3x minus 0.4 multiply 1 is equal to 0.5 x plus 1 0.4 into 3 it becomes 1.2 x minus 0.4 is equal to 0.5 x plus 1 now we separate out the variables there are two variables 1.2 x and 0.5 x so 1.2 x when 0.5 go to the other side by the process of transposition then it becomes minus 0.5 x now 1 minus 0.4 when it goes to the right side then it becomes plus 0.4 now we solve this 1.2 minus 0.5 then it becomes 0.7 and 1 plus 0.4 then it becomes 1.4 now the value of x 1.4 divided by 0.7 okay so when we remove that point then we multiply by 10 because we remove the decimal from 7 and again in denominator we multiply by 10 also so 10 10 cancel out by each other 7 and 7 2 so the value of x is equal to 2 so this is our answer i hope you like this video so please subscribe leto for more updates and do comment your questions thank you"
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