# NCERT Exemplar Solutions Class 8 Mathematics Solutions for Linear Equations in One Variable - Exercise in Chapter 4 - Linear Equations in One Variable

Question 5 Linear Equations in One Variable - Exercise

If (5x/3) – 4 = (2x/5), then the numerical value of 2x – 7 is

(a) 19/13

(b) -13/19

(c) 0

(d) 13/19

(b) -13/19

Given, (5x/3) – 4 = (2x/5)

(5x/3) - (2x/5) = 4

LCM of 3 and 5 is 15

(25x – 6x)/15 = 4

19x = 4 × 15

19x = 60

X = 60/19

Then, Substitute the value of x in 2x -7

= (2 × (60/19)) – 7

= (120/19) – 7

= (120 - 133)/19

= - 13/19

Video transcript
"hello students i am rita your math leader tutor and the today's question is if 5x by 3 minus 4 is equal to 2x by 5 then the numerical value of 2x minus 7 is the option is 19 by 13 b is minus 13 by 19 c is 0 and the option d is 13 by 19. first of all we solve this equation 5x minus 3 first we separate out the variable and constant term minus 4 when it goes there by the process of transposition it becomes plus now the lcm of 3 and 5 is 15 so 3 5's are 15 5 5's are 25 x minus 5 3's are 15 then two 3's are 6 is equal to 4 now we cross multiply here by applying cross multiply so 25 minus 6 it becomes 19x and 15 into 4 it becomes 60 now the value of x is equal to 60 by 19 so this is the value of x but in the question we have to find the value of 2 x minus 7 so we put the value of x 2 into 60 by 19 minus 7 by 1 so it becomes 120 by 19 minus 7 by 1 calcium is 19 so 120 minus 19 into 7 so it becomes 120 minus 133 so it becomes minus 13 by 90 so this is our answer minus 13 by 19 it means option b is correct so minus 13 by 19 this is our answer i hope you like this video so please subscribe lido for more updates and do comment your questions thank you"
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