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A and B are together 90 years old. Five years ago A was thrice as old as B was. Hence, the ages of A and B five years back would be (x – 5) years and (85 – x) years respectively.

Answer:

True.

Let us assume age of A be y years.

So, age of B = (90 - y) years.

Then,

Before 5 years A’s age = (x - 5) years

and B’s age = (90 – x - 5) = (85 - x) years.

"hello students i am rita your math
leader tutor and the today's question is
a and b are together 90 years old
five years ago e was thrice as old
as b was hence the ages of a
and b 5 years ago would be
x minus 5 years and 85
minus x years respectively and the
answer of this question
is true now we solve this question
let it is given that a plus b
ages of a plus b is equal to 90
years let the age of a be
x then the age of
b will become 90
minus x is age of
b and we let the age
of a is equal to x years
then the age of b will become 90 minus
x years okay now five years
ago five years ago
each h of a is equal to
x minus 5 and 5 years
ago h of b
is equal to 90 minus x
minus 5 so it becomes 90 minus 5 85
minus x years
and x minus 5 year so
and in the question same thing is given
to us x minus 5 years and 85 minus
x is that's why its answer is true i
hope you like this video so please
subscribe lido for more updates and do
comment your questions
thank you"

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