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A and B are together 90 years old. Five years ago A was thrice as old as B was. Hence, the ages of A and B five years back would be (x – 5) years and (85 – x) years respectively.

• Solution

• Transcript

True.

Let us assume age of A be y years.

So, age of B = (90 - y) years.

Then,

Before 5 years A’s age = (x - 5) years

and B’s age = (90 – x - 5) = (85 - x) years.

"hello students i am rita your math leader tutor and the today's question is a and b are together 90 years old five years ago e was thrice as old as b was hence the ages of a and b 5 years ago would be x minus 5 years and 85 minus x years respectively and the answer of this question is true now we solve this question let it is given that a plus b ages of a plus b is equal to 90 years let the age of a be x then the age of b will become 90 minus x is age of b and we let the age of a is equal to x years then the age of b will become 90 minus x years okay now five years ago five years ago each h of a is equal to x minus 5 and 5 years ago h of b is equal to 90 minus x minus 5 so it becomes 90 minus 5 85 minus x years and x minus 5 year so and in the question same thing is given to us x minus 5 years and 85 minus x is that's why its answer is true i hope you like this video so please subscribe lido for more updates and do comment your questions thank you"

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