The digit in the tens place of a two digit number is 3 more than the digit in the units place. Let the digit at units place be b. Then the number is
(a) 11b + 30 (b) 10b + 30 (c) 11b + 3 (d) 10b + 3
(a) 11b + 30
From the question it is given that,
Let the digit at units place be b.
The digit in the tens place of a two digit number is 3 more than the digit in the units place = 3 + b
So, the number = 10 (3 + b) + b
= 30 + 10b + b
= 30 + 11b
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