A four-digit number 4ab5 is divisible by 55. Then the value of b – a is
(a) 0
(b) 1
(c) 4
(d) 5
The correct answer is option (b) 1
Explanation:
We know that the four digit number 4ab5 which is divisible by 55 is also divisible by 11 and
also the factors of it. By using the divisibility test of 11, the difference between the sum of the
alternate digits should be a multiple of 11.
It means that
(4+b) – (a+5) =0, 11, 22, …it becomes
b – a - 1 = 0
Hence, b-a= 1
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