A 5.5m long ladder is leaned against a wall. The ladder reaches the wall to a height of 4.4m. Find the distance between the wall and the foot of the ladder.
Let us consider the right angle triangle PQR
Given,
Long ladder i.e. RQ = 5.5 m
The ladder reaches the wall to a height i.e. PR = 4.4 m
From Pythagoras theorem,
\begin{array}{l} \mathrm{RQ}^{2}=\mathrm{RP}^{2}+\mathrm{PQ}^{2} \\ 5.5^{2}=4.4^{2}+\mathrm{PQ}^{2} \\ \mathrm{PQ}^{2}=5.5^{2}-4.4^{2} \\ \mathrm{PQ}=\mathrm{V}\left(5.5^{2}-4.4^{2}\right) \\ \mathrm{PQ}=\mathrm{V}(30.25-19.36) \\ \mathrm{PQ}=\sqrt{10.89} \end{array}
PQ = 3.3
∴ The distance between the wall and the foot of the ladder is 3.3 m.
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