# NCERT Exemplar Solutions Class 7 Mathematics Solutions for Comparing Quantities - Exercise in Chapter 7 - Comparing Quantities

Question 44 Comparing Quantities - Exercise

A fruit seller purchased 20 kg of apples at ₹ 50 per kg. Out of these, 5% of the apples were found to be rotten. If he sells the remaining apples at ₹ 60 per kg, then his _________is _________%.

A fruit seller purchased 20 kg of apples at ₹ 50 per kg. Out of these, 5% of the apples were found to be rotten. If he sells the remaining apples at ₹ 60 per kg, then his profit is 14 %.

From the question it is given that, A fruit seller purchased 20 kg of apples at ₹ 50 per kg

In that 20 kg of apples 5% were rotten, so good apples = 20 – 5% of 20kg

= 20 – (5/100) × 20

= 20 – (100/100)

= 20 – 1

= 19 kg

So, 19 kg apples were sold at ₹ 60 per kg

Then, total Selling price of apples = 19 × 60

= ₹ 1140

Given cost price of 20 kg of apples = 20 × 50

= ₹ 1000

SP is more than CP so, Profit = SP – CP

= 1140 – 1000

= ₹ 140

We know that, Profit percentage = (Profit/CP) × 100

= (140/1000) × 100

= 14%

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