 # NCERT Exemplar Solutions Class 7 Mathematics Solutions for Comparing Quantities - Exercise in Chapter 7 - Comparing Quantities

A farmer bought a buffalo for ₹ 44000 and a cow for ₹ 18000. He sold the buffalo at a loss of 5% but made a profit of 10% on the cow. The net result of the transaction is

(a) loss of ₹ 200 (b) profit of ₹ 400

(c) loss of ₹ 400 (d) profit of ₹ 200

(c) loss of ₹ 400

From the question it is given that,

Cost price of cow = ₹ 18000

Profit percent on cow = 10%

We know that, Profit percent = (Profit/CP) × 100

10 = (Profit/₹ 18000) × 100

(10 × 18000)/100 = Profit

Profit = 10 × 180

Profit = ₹ 1800

Then, Profit = SP – CP

1800 = SP – 18000

SP = 1800 + 18000

SP of cow = ₹ 19800

Cost price of buffalo = ₹ 44000

He sold the buffalo at a loss of 5%

We know that, Loss percent = (loss/CP) × 100

5 = (loss/44000) × 100

(5 × 44000)/100 = loss

Loss = 5 × 440

Loss = ₹ 2200

Loss = CP – SP

₹2200 = ₹44000 – SP

SP = 44000 – 2200

SP of buffalo = ₹ 41,800

Now,

Total cost price of both buffalo and cow = ₹ 44000 + ₹ 18000

= ₹ 62000

Total selling price of both buffalo and cow = ₹ 41800 + ₹ 19800

= ₹ 61,600

Selling price of both buffalo and cow is less when compare to cost price,

So, Loss = CP – SP

= ₹ 62000 – ₹ 61600

Loss = ₹ 400

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