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Integers | Integers - Exercise

Question 193

A ribbon of length 5¼ m is cut into small pieces each of length ¾m. A number of pieces will be:

(a) 5 (b) 6 (c) 7 (d) 8

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(c) 7

First we have to convert the mixed fraction into improper fraction 5¼ = 21/4

Then, 21/4 ÷ ¾

= (21/4)/ (¾)

= (21/4) × (4/3)

= (21 × 4)/ (4 × 3)

= (7 × 1)/ (1 × 1)

= 7

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Our top 5% students will be awarded a special scholarship to Lido.

subject-cta

Question 193

A ribbon of length 5¼ m is cut into small pieces each of length ¾m. A number of pieces will be:

(a) 5 (b) 6 (c) 7 (d) 8

Looking to do well in your science exam ? Learn from an expert tutor. Book a free class!

(c) 7

First we have to convert the mixed fraction into improper fraction 5¼ = 21/4

Then, 21/4 ÷ ¾

= (21/4)/ (¾)

= (21/4) × (4/3)

= (21 × 4)/ (4 × 3)

= (7 × 1)/ (1 × 1)

= 7

Our top 5% students will be awarded a special scholarship to Lido.

subject-cta
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