Jump to

Mathematics textbook for Class VI has 320 pages. The chapter ‘symmetry’ runs from page 261 to page 272. The ratio of the number of pages of this chapter to the total number of pages of the book is

(A) 11 : 320 (B) 3 : 40 (C) 3 : 80 (D) 272 : 320

Answer:

(C) 3 : 80

From the question it is given that,

Total number of pages in the Mathematics textbook for Class VI = 320 pages

The chapter ‘symmetry’ runs from page 261 to page 272

Number of pages contains symmetry chapter = 12

So, the ratio of the number of pages of this chapter to the total number of pages of the

book is,

= 12/320

Divide both numerator and denominator by 12.

= 6/160

Again, divide both numerator and denominator by 2.

= 3/80

Therefore, the ratio of the number of pages of this chapter to the total number of pages

of the book is 3: 80.

"hello students welcome to leader q a
video session i am saf your max tutor
and question for today is a rhombus
shaped field has
green grass for 18 cows to graze
if each side of the rhombus is 30 meter
and its longer diagonal is 48 meter
how much area of grass field will each
cow be getting
so first of all you draw the rhombus
shape field with the vertices
as shown in the figure so this rhombus
abcd is a
field as per the question
and you can see inside this rhombus
diagonal ac is there
which divides the rhombus into two
congruent triangles
and these triangles are triangle adb
and triangle bdc
or bcd
now consider triangle bcd inside this
triangle
first of all let us find semi parameter
to find its area
so s will be equal to 48
sum all the side and then divided by 2
so s will be equal to 54 meter
now use the harrows formula to find the
area so as per the harrows formula you
know
let it indicate as a that is area of the
triangle
so area will be equal to under root of
s s minus a s minus
b as minus c
let us substitute value of a b c and s
so this will give you
as is 54 54
minus 48
and then 54 minus 30
and then 54 minus 30 again
so this is our arrows formula applied we
will continue over here
so area comes out to be a is equal to
432 meter square
and hence area of the field will be 2
into
area of triangle bcd
because this field is made up of two
triangles
which are congruent as these two
triangles are congruent their area will
also be same
so you can say that this area of
triangle
abd will be equal to area of triangle
bcd
so you can see here that
the area of the field will be equal to 2
into area of
triangle bc d that is 2
into 432
the area will be equal to 864 meter
square
thus the area of the grass filled at
each
cow that each cow will be great grazing
will be equal to
864 meter square
divided by 18 as you can see there are
18 cows
we have to divide it by 18 for finding
the area grazed by each cow
864 divided by 18
and that comes out to be 48
square and that is our final answer
for the area area of the grass grazed by
each cow if you have any query you can
post it in our comment section
and subscribe to lido for more such q
and a thank you for watching
"

Related Questions

Was This helpful?

Lido

Courses

Quick Links

Terms & Policies

Terms & Policies

2022 © Quality Tutorials Pvt Ltd All rights reserved