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A picture is 60cm wide and 1.8m long. The ratio of its width to its perimeter in

lowest form is

(A) 1 : 2 (B) 1 : 3 (C) 1 : 4 (D) 1 : 8

• Solution

• Transcript

(D) 1 : 8

From the question it is given that,

Width of a picture = 60 cm

Length of a picture = 1.8 m

We know that, 1 m = 100 cm

So, 1.8 m = 180 cm

Perimeter of rectangle = 2 (length + breadth)

= 2 (180 + 60)

= 2 (240)

= 480

Therefore, The ratio of its width to its perimeter in lowest form = 60/480

Divide both numerator and denominator by 20.

= 3/24

Again, divide both numerator and denominator by 3.

= 1/8

= 1 : 8

"hello students welcome to lido q a video session i am seph your math tutor and question for today is an isosceles triangle has a parameter 30 centimeter and each of the equal side is 12 centimeter find the area of the triangle so in the question it is given that length of equal sides is 12 centimeter each and perimeter of given isosceles triangle is 30 centimeter so 30 will be equal to 12 plus 12 plus let the third side be x so the length of the third side will be x is equal to 30 minus 24 so it is 6 centimeter thus the semi perimeter of the isosceles triangle will be equal to 12 plus 12 plus 6 upon 2 that is 30 upon 2 and that comes out to be 15 centimeter once you found the value of s you can easily find the area so area of given isosceles triangle will be equal to root of s s minus a s minus b s minus c where abc are the three sides of isosceles triangle so root of 15 15 minus 12 15 minus 12 and 15 minus 6 so we can write area a will be equal to root of 15 into 3 into 3 into 9 and that is 9 under root 15 centimeter square so area of the triangle is 9 root 15 centimeter square if you have any query you can drop it in our comment section and subscribe to lido for more such q a thank you for watching "

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