Ncert exemplar solutions Our top 5% students will be awarded a special scholarship to Lido.
Set your child up for success with Lido, book a class today!

16/36 = ( )/63 = 36/( ) = ( )/117 Looking to do well in your science exam ? Learn from an expert tutor. Book a free class!

Consider the first two ratios 16/36 = [ ]/63

Let us assume the missing number be P

Then, 16/36 = P/63

By cross multiplication we get,

P = (16 × 63)/36

P = 1008/36

Divide both numerator and denominator by 36.

P = 28

Therefore, 16/36 = /63

Now, consider the middle two ratios, 28/63 = 36/[ ]

Let us assume the missing number be Q,

Then, 28/63 = 36/Q

By cross multiplication we get,

Q = (36 × 63)/28

Q = 2268/28

Divide both numerator and denominator by 28.

Q = 81

Therefore, 28/63 = 36/

Consider the last two ratios 36/81 = [ ]/117

Let us assume the missing number be R

Then, 28/63 = R/117

By cross multiplication we get,

P = (28 × 117)/63

P = 3276/63

Divide both numerator and denominator by 63.

P = 52

Therefore, 36/81 = /117

So, 16/36 = /63 = 36/ = /117

Our top 5% students will be awarded a special scholarship to Lido. Lido

Courses

Teachers

Book a Demo with us

Syllabus

Science
English
Coding

Terms & Policies

NCERT Question Bank

Maths
Science

Selina Question Bank

Maths
Physics
Biology

Allied Question Bank

Chemistry