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Ratio and Proportion | Exercise

Question 15

16/36 = ( )/63 = 36/( ) = ( )/117

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Consider the first two ratios 16/36 = [ ]/63

Let us assume the missing number be P

Then, 16/36 = P/63

By cross multiplication we get,

P = (16 × 63)/36

P = 1008/36

Divide both numerator and denominator by 36.

P = 28

Therefore, 16/36 = [28]/63

Now, consider the middle two ratios, 28/63 = 36/[ ]

Let us assume the missing number be Q,

Then, 28/63 = 36/Q

By cross multiplication we get,

Q = (36 × 63)/28

Q = 2268/28

Divide both numerator and denominator by 28.

Q = 81

Therefore, 28/63 = 36/[81]

Consider the last two ratios 36/81 = [ ]/117

Let us assume the missing number be R

Then, 28/63 = R/117

By cross multiplication we get,

P = (28 × 117)/63

P = 3276/63

Divide both numerator and denominator by 63.

P = 52

Therefore, 36/81 = [52]/117

So, 16/36 = [28]/63 = 36/[81] = [52]/117

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Our top 5% students will be awarded a special scholarship to Lido.

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Question 15

16/36 = ( )/63 = 36/( ) = ( )/117

Looking to do well in your science exam ? Learn from an expert tutor. Book a free class!

Consider the first two ratios 16/36 = [ ]/63

Let us assume the missing number be P

Then, 16/36 = P/63

By cross multiplication we get,

P = (16 × 63)/36

P = 1008/36

Divide both numerator and denominator by 36.

P = 28

Therefore, 16/36 = [28]/63

Now, consider the middle two ratios, 28/63 = 36/[ ]

Let us assume the missing number be Q,

Then, 28/63 = 36/Q

By cross multiplication we get,

Q = (36 × 63)/28

Q = 2268/28

Divide both numerator and denominator by 28.

Q = 81

Therefore, 28/63 = 36/[81]

Consider the last two ratios 36/81 = [ ]/117

Let us assume the missing number be R

Then, 28/63 = R/117

By cross multiplication we get,

P = (28 × 117)/63

P = 3276/63

Divide both numerator and denominator by 63.

P = 52

Therefore, 36/81 = [52]/117

So, 16/36 = [28]/63 = 36/[81] = [52]/117

Our top 5% students will be awarded a special scholarship to Lido.

subject-cta
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