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(7 /12) + (11/12) = 3/2

Answer:

Consider Left Hand Side (LHS),

Sum of like fractions= (7 /12) + (11/12)

= (7 + 11)/12

= 18/12

Divide both numerator and denominator by 6, we get,

= 3/2

Right Hand Side (RHS) = 3/2

By comparing LHS and RHS,

LHS = RHS

3/2 = 3/2

"hello students welcome to lido q a video
session i am saf
your math tutor and question for today
is abc
and adc are two right triangles
with common hypotenuse ac prove that
angle cad equals to angle cbd
we know that ac is common so
ac is common hypotenuse
angle b and angle d is 90 degree
so angle b equal to angle d equal to 90
degree
now it has to be proven that angle cad
equal to angle cbd
now you can see the figure angle abc and
angle adc are 90 degrees
now since abc and adc are 90 degree
it can be said that they lie on the
semicircle
so since abc and adc are 90 degree they
lie on the semicircle
remember the angle which is formed
inside the semicircle
is 90 degree
so triangle abc and adc are in the
semicircle
they are right triangles
and point a b c and d
are con cyclic
hence cd is the chord of the circle with
center o
we can say that
and we know that angles which are in the
same segment of the circle
are always equal so here two angles
angle cad
and angle cbd they are in the same
segment of the circle
so they are equal
and angle cad is equal to angle cbd
is the required proof hands prove
if you have any queries you can drop it
in our comment section
and subscribe to lido for more such q a
thank you for watching"

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