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NCERT Exemplar Solutions Class 6 Mathematics Solutions for Exercise in Chapter 4 - Fractions and Decimals
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9 + (2/10) + (6/100) is equal to the decimal number ____
Answer:
9 + (2/10) + (6/100) is equal to the decimal number 9.26.
Fractions with denominators 10,100, etc. can be written in a form, using a decimal point, called decimal numbers or decimals.
9 + (2/10) + (6/100) = 9 + 0.2 + 0.06
= 9.26
Video transcript
"hello students welcome to lido q a video
session i am saf your math tutor and
question for today is
v is the volume of a cuboid of a
dimension a b
c and s is the surface area then prove
that
1 upon b which will be equal to
2 upon s bracket of 1 upon a plus 1 upon
b
plus 1 upon c bracket close so here
we need to prove this prove this
first of all we need to see the question
question is
the dimensions are given in the question
you can see dimension of the q
bar length
which is l and that is equal to a
breadth
that is b and that is equal to
b that is given in the question height
and that is h and that is c
now we know that the volume of the cube
can be given by the formula
length into breadth into height
volume of the cuboid which is equal to
length into breath into height
now this can also be written as
a into b into c because from the
question
all these dimensions are having
measurements length a breadth b
height in c
which would be equal to abc and that is
the volume of cuboid
now again surface area of a cube s is
equal to
so we have the formula for surface area
s is equal to 2 into
bracket of lb plus
bh plus hl
length breadth and height are lb and h
respectively
so you can write this like s is equal to
2 into length is a breadth is b
height is c
a b plus b c
plus c a
now let us name this as
equation number two
and this name let us name this volume of
the cuboid as equation number
one considering this one and two in mind
we have from the question one upon v is
equal to
2 upon s bracket of 1 upon a plus 1 upon
b plus 1 upon c that is in the question
so we need to first of all take
allergies from the prove that
from the prove that lhs is equal to
2 upon s 1 upon a plus
1 upon b plus 1 upon c and that is the
lhs if you take lcm then 2 upon s
will be equal to ab plus
bc plus
ca divided by
abc
so here you can substitute the value of
s from the equation number two
so from two
you have
2 upon 2 into
a b plus bc plus ca
into a b
plus b c plus c a
upon abc
so simplifying this it will give you 1
upon abc
and this 1 upon abc will be equal to 1
upon b
which is exactly equal to your
left hand side that is left hand side
which is equal to right hand side from
the question
so this was from the question
your right hand side
i'll see over here right hand side and
which is equal to
left hand side
hence lhs is equal to i rhs either way
so this this is the proved statement now
hence prove
if you have any doubt you can drop it
down in our comment section
and subscribe to lido for more such
interesting q a sessions
thank you for watching"
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