NCERT Exemplar Solutions Class 6 Mathematics Solutions for Exercise in Chapter 4 - Fractions and Decimals

Question 33 Exercise

9 + (2/10) + (6/100) is equal to the decimal number ____


9 + (2/10) + (6/100) is equal to the decimal number 9.26.

Fractions with denominators 10,100, etc. can be written in a form, using a decimal point, called decimal numbers or decimals.

9 + (2/10) + (6/100) = 9 + 0.2 + 0.06

= 9.26

Video transcript
"hello students welcome to lido q a video session i am saf your math tutor and question for today is v is the volume of a cuboid of a dimension a b c and s is the surface area then prove that 1 upon b which will be equal to 2 upon s bracket of 1 upon a plus 1 upon b plus 1 upon c bracket close so here we need to prove this prove this first of all we need to see the question question is the dimensions are given in the question you can see dimension of the q bar length which is l and that is equal to a breadth that is b and that is equal to b that is given in the question height and that is h and that is c now we know that the volume of the cube can be given by the formula length into breadth into height volume of the cuboid which is equal to length into breath into height now this can also be written as a into b into c because from the question all these dimensions are having measurements length a breadth b height in c which would be equal to abc and that is the volume of cuboid now again surface area of a cube s is equal to so we have the formula for surface area s is equal to 2 into bracket of lb plus bh plus hl length breadth and height are lb and h respectively so you can write this like s is equal to 2 into length is a breadth is b height is c a b plus b c plus c a now let us name this as equation number two and this name let us name this volume of the cuboid as equation number one considering this one and two in mind we have from the question one upon v is equal to 2 upon s bracket of 1 upon a plus 1 upon b plus 1 upon c that is in the question so we need to first of all take allergies from the prove that from the prove that lhs is equal to 2 upon s 1 upon a plus 1 upon b plus 1 upon c and that is the lhs if you take lcm then 2 upon s will be equal to ab plus bc plus ca divided by abc so here you can substitute the value of s from the equation number two so from two you have 2 upon 2 into a b plus bc plus ca into a b plus b c plus c a upon abc so simplifying this it will give you 1 upon abc and this 1 upon abc will be equal to 1 upon b which is exactly equal to your left hand side that is left hand side which is equal to right hand side from the question so this was from the question your right hand side i'll see over here right hand side and which is equal to left hand side hence lhs is equal to i rhs either way so this this is the proved statement now hence prove if you have any doubt you can drop it down in our comment section and subscribe to lido for more such interesting q a sessions thank you for watching"
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