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Fractions and Decimals | Exercise

Question 30

18/135 and 90/675 are proper, unlike and ____ fractions.

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  • Solution

  • Transcript

18/135 and 90/675 are proper, unlike and equivalent fractions.

Consider the two given fraction, 18/135 and 90/675

So, (18/135)=(90/675)

By cross multiplication, we get

(18 X 675) = (90 X 135)

12,150 = 12,150

Therefore, 18/135 and 90/675 are proper, unlike and equivalent fractions.

"hello students welcome to lido q a video session i'm sev your math tutor and question for today is a cuboidal vessel is 10 meter long and 8 meter wide how high must it be made to hold 380 cubic meters of a liquid here dimension of the capital vessel is given to you length which is l and it is equal to 10 meter breadth b which is equal to 8 meter and the volume of the vessel is given that is 380 meter cube let h be the height of the cuboidal vessel which we need to find now we already know through the volume of the cuboidal vessel we have one formula that is length into breath into height so volume and that is equal to already given to us one volume that is 380 meter cube so let us equate this 380 meter cube with length into breath into h so 380 will be equal to length is 10 breath is 8 and h we need to find so h is equal to 10 into 8 h is equal to 380 divided by 10 into 8 and this will give you after simplification it will give you height will be equal to 4.75 so that is the value of h therefore from this we can write the height of vessel should be 4.75 meter if you have any doubt regarding this you can post it in our comment section and subscribe to lido for more such interesting q a sessions thank you for watching "

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Question 30

18/135 and 90/675 are proper, unlike and ____ fractions.

  • Solution

  • Transcript

18/135 and 90/675 are proper, unlike and equivalent fractions.

Consider the two given fraction, 18/135 and 90/675

So, (18/135)=(90/675)

By cross multiplication, we get

(18 X 675) = (90 X 135)

12,150 = 12,150

Therefore, 18/135 and 90/675 are proper, unlike and equivalent fractions.

"hello students welcome to lido q a video session i'm sev your math tutor and question for today is a cuboidal vessel is 10 meter long and 8 meter wide how high must it be made to hold 380 cubic meters of a liquid here dimension of the capital vessel is given to you length which is l and it is equal to 10 meter breadth b which is equal to 8 meter and the volume of the vessel is given that is 380 meter cube let h be the height of the cuboidal vessel which we need to find now we already know through the volume of the cuboidal vessel we have one formula that is length into breath into height so volume and that is equal to already given to us one volume that is 380 meter cube so let us equate this 380 meter cube with length into breath into h so 380 will be equal to length is 10 breath is 8 and h we need to find so h is equal to 10 into 8 h is equal to 380 divided by 10 into 8 and this will give you after simplification it will give you height will be equal to 4.75 so that is the value of h therefore from this we can write the height of vessel should be 4.75 meter if you have any doubt regarding this you can post it in our comment section and subscribe to lido for more such interesting q a sessions thank you for watching "

Our top 5% students will be awarded a special scholarship to Lido.

subject-cta
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