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Ncert exemplar solutions
Grade 6 
Mathematics
Mathematics Exemplar Problems - class 6
Fractions and Decimals
Exercise
Question 15
Mathematics
Mathematics Exemplar Problems - class 6
Fractions and Decimals
Exercise
Question 15
Fractions and Decimals | Exercise
Question 15
CHAPTERS
0.07 + 0.008 is equal to
(A) 0.15
(B) 0.015
(C) 0.078
(D) 0.78
(c) 0.078
= (35 + 4)/7
= 39/7
First we have to convert given decimals into like decimals= 0.070 + 0.008
So, sum of 0.070 and 0.008 = 0.070 + 0.008
=0.078
Question 15
0.07 + 0.008 is equal to
(A) 0.15
(B) 0.015
(C) 0.078
(D) 0.78
(c) 0.078
= (35 + 4)/7
= 39/7
First we have to convert given decimals into like decimals= 0.070 + 0.008
So, sum of 0.070 and 0.008 = 0.070 + 0.008
=0.078
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