 # NCERT Solutions Class 9 Mathematics Solutions for Areas of Parallelograms and Triangles - Exercise 9.2 in Chapter 9 - Areas of Parallelograms and Triangles

Question 3 Areas of Parallelograms and Triangles - Exercise 9.2

A farmer was having a field in the form of a parallelogram PQRS. She took any point A on RS and joined it to points P and Q. In how many parts the fields is divided? What are the shapes of these parts? The farmer wants to sow wheat and pulses in equal portions of the field separately. How should she do it? The field is divided into three parts each in a triangular shape.

Let, ΔPSA, ΔPAQ and ΔQAR be the triangles.

Area of ΔPSA + ΔPAQ + ΔQAR = Area of PQRS --- (i)

Area of ΔPAQ =1/2 area of PQRS --- (ii)

Here, the triangle and parallelogram are on the same base and in-between the same parallel lines.

From (i) and (ii),

Area of ΔPSA + Area of ΔQAR =1/2 area of PQRS --- (iii)

From (ii) and (iii), we can conclude that,

The farmer must sow wheat or pulses in ΔPAQ or either in both ΔPSA and ΔQAR.

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