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Surface Areas and Volumes | Surface Areas and Volumes - Exercise 13.8

Question 6

.A hemispherical tank is made up of an iron sheet 1 cm thick. If the inner radius is 1 m, then

find the volume of the iron used to make the tank. (Assume π = 22/7)

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Inner Radius of the tank, (r ) = 1m

Outer Radius (R ) = 1.01m

The volume of the iron used in the tank = 2 / 3 \pi\left(\mathrm{R}^{3}-\mathrm{r}^{3}\right)

Put values,

Volume of the iron used in the hemispherical tank = 2/3 x 22/7 x \left(1.01^{3}-1^{3}\right)=0.06348

So volume of the iron used in the hemispherical tank is 0.06348 \mathrm{m}^{3}

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Question 6

.A hemispherical tank is made up of an iron sheet 1 cm thick. If the inner radius is 1 m, then

find the volume of the iron used to make the tank. (Assume π = 22/7)

Looking to do well in your science exam ? Learn from an expert tutor. Book a free class!

Inner Radius of the tank, (r ) = 1m

Outer Radius (R ) = 1.01m

The volume of the iron used in the tank = 2 / 3 \pi\left(\mathrm{R}^{3}-\mathrm{r}^{3}\right)

Put values,

Volume of the iron used in the hemispherical tank = 2/3 x 22/7 x \left(1.01^{3}-1^{3}\right)=0.06348

So volume of the iron used in the hemispherical tank is 0.06348 \mathrm{m}^{3}

Our top 5% students will be awarded a special scholarship to Lido.

subject-cta
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