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- Surface Areas and Volumes - Exercise 13.1
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- Surface Areas and Volumes - Exercise 13.3
- Surface Areas and Volumes - Exercise 13.4
- Surface Areas and Volumes - Exercise 13.5
- Surface Areas and Volumes - Exercise 13.6
- Surface Areas and Volumes - Exercise 13.7
- Surface Areas and Volumes - Exercise 13.8
- Surface Areas and Volumes - Exercise 13.9
NCERT Solutions Class 9 Mathematics Solutions for Surface Areas and Volumes - Exercise 13.8 in Chapter 13 - Surface Areas and Volumes
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.A hemispherical tank is made up of an iron sheet 1 cm thick. If the inner radius is 1 m, then
find the volume of the iron used to make the tank. (Assume π = 22/7)
Answer:
Inner Radius of the tank, (r ) = 1m
Outer Radius (R ) = 1.01m
The volume of the iron used in the tank = 2 / 3 \pi\left(\mathrm{R}^{3}-\mathrm{r}^{3}\right)
Put values,
Volume of the iron used in the hemispherical tank = 2/3 x 22/7 x \left(1.01^{3}-1^{3}\right)=0.06348
So volume of the iron used in the hemispherical tank is 0.06348 \mathrm{m}^{3}
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