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- Surface Areas and Volumes - Exercise 13.1
- Surface Areas and Volumes - Exercise 13.2
- Surface Areas and Volumes - Exercise 13.3
- Surface Areas and Volumes - Exercise 13.4
- Surface Areas and Volumes - Exercise 13.5
- Surface Areas and Volumes - Exercise 13.6
- Surface Areas and Volumes - Exercise 13.7
- Surface Areas and Volumes - Exercise 13.8
- Surface Areas and Volumes - Exercise 13.9
NCERT Solutions Class 9 Mathematics Solutions for Surface Areas and Volumes - Exercise 13.8 in Chapter 13 - Surface Areas and Volumes
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The diameter of a metallic ball is 4.2 cm. What is the mass of the ball, if the density of the metal
is 8.9 g per cm3? (Assume π = 22/7)
Answer:
diameter of a metallic ball = 4.2 cm
Radius(r) of the metallic ball, r = 4.2/2 cm = 2.1 cm
Now, using relationship between, density, mass and volume,
Density = Mass/Volume
Mass = Density x volume
= (8.9 x 38.808) g
= 345.3912 g
The mass of the ball is 345.39 g (approx).
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