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- Surface Areas and Volumes - Exercise 13.1
- Surface Areas and Volumes - Exercise 13.2
- Surface Areas and Volumes - Exercise 13.3
- Surface Areas and Volumes - Exercise 13.4
- Surface Areas and Volumes - Exercise 13.5
- Surface Areas and Volumes - Exercise 13.6
- Surface Areas and Volumes - Exercise 13.7
- Surface Areas and Volumes - Exercise 13.8
- Surface Areas and Volumes - Exercise 13.9
NCERT Solutions Class 9 Mathematics Solutions for Surface Areas and Volumes - Exercise 13.7 in Chapter 13 - Surface Areas and Volumes
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Question 9 Surface Areas and Volumes - Exercise 13.7
A heap of wheat is in the form of a cone whose diameter is 10.5 m and height is 3 m. Find its
volume. The heap is to be covered by canvas to protect it from rain. Find the area of the canvas.
(Assume π = 22/7)
Answer:
Radius (r) of heap = (10.5/2) m = 5.25
Height (h) of heap = 3m
\text { Volume of heap }=1 / 3 \pi \mathrm{r}^{2} \mathrm{h}
= 1/3 x 22/7 x 5.25 x 5.25 x 3
= 86.625
The volume of the heap of wheat is
86.625 \mathrm{m}^{3}
Again,
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