A conical pit of top diameter 3.5 m is 12 m deep. What is its capacity in kiloliters?
(Assume π = 22/7)
Diameter of conical pit = 3.5
Radius of conical pit, r = diameter/ 2 = (3.5/2) m = 1.75 m
Height of pit, h = Depth of pit = 12 m
\begin{aligned} &\text { Volume of cone, } V=(1 / 3) \pi \mathrm{r}^{2} \mathrm{h}\\ &V=1 / 3 \times 22 / 7 \times(1.75)^{2} \times 12=38.5\\ &\text { Volume of cone is } 38.5 \mathrm{m}^{3} \end{aligned}
Hence, capacity of the pit = (38.5 x 1) kiloliters = 38.5 kiloliters.
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