A hemispherical bowl is made of steel, 0.25 cm thick. The inner radius of the bowl is 5cm. Find
the outer curved surface of the bowl. (Assume π = 22/7)
Given:
The inner radius of hemispherical bowl = 5 cm
The thickness of the bowl = 0.25 cm
Outer radius of hemispherical bowl = (5 + 0.25) cm = 5.25 cm
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