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- Surface Areas and Volumes - Exercise 13.1
- Surface Areas and Volumes - Exercise 13.2
- Surface Areas and Volumes - Exercise 13.3
- Surface Areas and Volumes - Exercise 13.4
- Surface Areas and Volumes - Exercise 13.5
- Surface Areas and Volumes - Exercise 13.6
- Surface Areas and Volumes - Exercise 13.7
- Surface Areas and Volumes - Exercise 13.8
- Surface Areas and Volumes - Exercise 13.9

Find the cost of digging a cuboidal pit 8 m long, 6 m broad, and 3 m deep at the rate of Rs 30 per \mathbf{m}^{3}

Answer:

The given pit has its length (l) as 8 m, width (b)as 6 m, and depth (h) as 3 m.

Volume of cuboidal pit = l x b x h = (8 x 6 x 3) = 144 (using formula)

The required Volume is 144 \mathbf{m}^{3}

"hello students welcome to lido q a video
session
i'm saf your math tutor and question for
today is
find the cost of digging a cuboidal pit
8 meter long 6 meter broad
and 3 meter deep at the rate of rupees
30 per meter cube
so the information which is given in the
questions are length
breadth and depth depth is considered as
height over here so the dimensions of
the cuboidal fit we will write down
first
length is 8 meter
breath that is b
that is six meter and depth
let us say it as h that is
three meter now volume of the cuboidal
pit is length into breath into height
so this is 8 into 6 into
3 and that is 144
144 meter cube
so the required volume is 144 meter cube
now it is given that the cost cost is
rupees 30 per meter
the digging cost is rupees 30 for 1
meter
so 144 meter cube cost will be how much
that we need to find
that will be 144 multiplied by 30
so that will be equal to 4320 rupees
so cost of digging
144 meter cube
is rupees four three two zero
that is our final answer if you have any
query regarding this you can drop it in
our comment section
and subscribe to lido for more such q a
thank you for watching"

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