In a hot water heating system, there is a cylindrical pipe of length 28 m and diameter of 5 cm. Find
the total radiating surface in the system. (Assume π=22/7)
Height of cylindrical pipe = Length of cylindrical pipe = 28 m
Radius of circular end of pipe = diameter/ 2 = 5/2 cm = 2.5 cm = 0.025 m
Now, CSA of cylindrical pipe = 2πrh, where r = radius and h = height of the cylinder
= 2 x 22/7 x 0.025 x 28 \mathrm{m}^{2}
=4.4 \mathrm{m}^{2}
The area of the radiating surface of the system is 4.4 \mathrm{m}^{2}
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