The inner diameter of a circular well is 3.5 m. It is 10 m deep. Find
(i) its inner curved surface area,
(ii) the cost of plastering this curved surface at the rate of Rs. 40 per \mathbf{m}^{2}
(Assume π=22/7)
Inner radius of circular well, r = 3.5/2m = 1.75m
Depth of circular well, say h = 10m
(i)Inner curved surface area = 2πrh
= ( 2 x 22/7 x 1.75 x 10)
= 110
Therefore, the inner curved surface area of the circular well is 110 \mathrm{m}^{2}
(ii)Cost of plastering 1 m area = Rs.40
Cost of plastering 110 m area = Rs (110 x 40) = Rs.4400
Therefore, the cost of plastering the curved surface of the well is Rs. 4400.
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