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- Surface Areas and Volumes - Exercise 13.1
- Surface Areas and Volumes - Exercise 13.2
- Surface Areas and Volumes - Exercise 13.3
- Surface Areas and Volumes - Exercise 13.4
- Surface Areas and Volumes - Exercise 13.5
- Surface Areas and Volumes - Exercise 13.6
- Surface Areas and Volumes - Exercise 13.7
- Surface Areas and Volumes - Exercise 13.8
- Surface Areas and Volumes - Exercise 13.9

Curved surface area of a right circular cylinder is 4.4 \mathbf{m}^{2}. If the radius of the base of

the cylinder is 0.7 m, find its height. (Assume π=22/7)

Answer:

Let h be the height of the circular cylinder and r be the radius.

The radius of the base of the cylinder, r = 0.7m

CSA of cylinder = 2πrh

CSA of cylinder = 4.4 \mathrm{m}^{2}

Equating both the equations, we have

2 x 22/7 x 0.7 x h = 4.4

Or h = 1

Therefore, the height of the cylinder is 1 m

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