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- Surface Areas and Volumes - Exercise 13.1
- Surface Areas and Volumes - Exercise 13.2
- Surface Areas and Volumes - Exercise 13.3
- Surface Areas and Volumes - Exercise 13.4
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- Surface Areas and Volumes - Exercise 13.6
- Surface Areas and Volumes - Exercise 13.7
- Surface Areas and Volumes - Exercise 13.8
- Surface Areas and Volumes - Exercise 13.9
NCERT Solutions Class 9 Mathematics Solutions for Surface Areas and Volumes - Exercise 13.2 in Chapter 13 - Surface Areas and Volumes
Question 1 Surface Areas and Volumes - Exercise 13.2
The curved surface area of a right circular cylinder of height 14 cm is 88 \mathrm{cm}^{2}. Find the diameter
of the base of the cylinder. (Assume π = 22/7 )
Answer:
Height of cylinder, h = 14cm
Let the diameter of the cylinder be d
Curved surface area of cylinder =88 \mathrm{cm}^{2}
We know that formula to find the Curved surface area of a cylinder is 2πrh. \text { So } 2 \pi \mathrm{m}=88 \mathrm{cm}^{2} (r is the radius of the base of the cylinder)
2×22/7×r ×14 =88 \mathrm{cm}^{2}
2r = 2 cm
d =2 cm
Therefore, the diameter of the base of the cylinder is 2 cm.
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