A triangle and a parallelogram have the same base and the same area. If the sides of the
triangle are 26 cm, 28 cm and 30 cm, and the parallelogram stands on the base 28 cm, find
the height of the parallelogram
Given,
It is given that the parallelogram and triangle have equal areas.
The sides of the triangle are given as 26 cm, 28 cm and 30 cm.
So, the perimeter = 26 + 28 + 30 = 84 cm
And its semi perimeter = 84/2 cm = 42 cm
Now, by using Heron's formula, the area of the triangle =
√[s (s-a) (s-b) (s-c)]
\begin{array}{l} =v[42(42-26)(46-28)(46-30)] \mathrm{cm}^{2} \\ =\sqrt{[46 \times 16 \times 14 \times 16] \mathrm{cm}^{2}} \end{array}
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