NCERT Solutions Class 8 Mathematics Solutions for Exercise 9.2 in Chapter 9 - Algebraic Expressions and Identities

Question 2 Exercise 9.2

Q1) Find the product of the following pairs of monomials:

(i) 4, 7p

(ii) -4p, 7p

(iii) -4p, 7pq

(iv) $4p^3,\ -3p$

(v) 4p, 0

Answer:

Solution:

(i) $4\times7p=4\times7\times p=28p$

(ii) $-4p\times7p=\left(-4\times7\right)\times\left(p\times p\right)=-28p^2$

(iii) $-4p\times7pq=\left(-4\times7\right)\left(p\times pq\right)=-28p^2q$

(iv) $4p^3\times-3p=\left(4\times-3\right)\left(p^3\times p\right)=-12p^4$

(v) $4p\times0=\left(4\times0\right)\left(p\right)=0$

Related Questions

Was This helpful?

Exercises

Exercise 9.1

Exercise 9.2

Exercise 9.3

Exercise 9.4

Exercise 9.5

Chapters

Rational Numbers

Linear Equations in One Variable

Understanding Quadrilaterals

Practical Geometry

Data Handling

Squares and Square Roots

Cubes and Cube Roots

Comparing Quantities

Algebraic Expressions and Identities

Visualising Solid Shapes

Mensuration

Exponents and Powers

Direct and Inverse Proportions

Factorisation

Introduction to Graphs

Playing with Numbers