Q1) Find the product of the following pairs of monomials:
(i) 4, 7p
(ii) -4p, 7p
(iii) -4p, 7pq
(iv) 4p^3,\ -3p
(v) 4p, 0
Solution:
(i) 4\times7p=4\times7\times p=28p
(ii) -4p\times7p=\left(-4\times7\right)\times\left(p\times p\right)=-28p^2
(iii) -4p\times7pq=\left(-4\times7\right)\left(p\times pq\right)=-28p^2q
(iv) 4p^3\times-3p=\left(4\times-3\right)\left(p^3\times p\right)=-12p^4
(v) 4p\times0=\left(4\times0\right)\left(p\right)=0
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