 # NCERT Solutions Class 8 Mathematics Solutions for Exercise 4.4 in Chapter 4 - Practical Geometry

Question 1 Exercise 4.4

DE = 4 cm

EA = 5 cm

AR = 4.5 cm

\begin{array}{l} \angle \mathrm{E}=60^{\circ} \\ \angle \mathrm{A}=90^{\circ} \end{array}

TR = 3.5 cm

RU = 3 cm

UE = 4 cm

\begin{array}{l} \angle \mathrm{R}=75^{\circ} \\ \angle \mathrm{U}=120^{\circ} \end{array}

(i) Rough Figure: (1) Draw a line segment DE of 4 cm and an angle of 60^{\circ} at point E. As vertex A is 5 cm away from vertex E, cut a line segment EA of 5 cm from this ray. (2) Again draw an angle of 90^{\circ} at point A. As vertex R is 4.5 cm away from vertex A, cut a line segment RA of 4.5 cm from this ray. (3) Join D to R. (ii) Rough Figure: (1) Draw a line segment RU of 3 cm and an angle of 120^{\circ} at point U. As vertex E is 4 cm away from vertex U, cut a line segment UE of 4 cm from this ray. (2) Next, draw an angle of 75^{\circ} at point R. As vertex T is 3.5 cm away from vertex R, cut a line segment RT of 3.5 cm from this ray. (3) Join T to E. Lido

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