- Rational Numbers
- Linear Equations in One Variable
- Understanding Quadrilaterals
- Practical Geometry
- Data Handling
- Squares and Square Roots
- Cubes and Cube Roots
- Comparing Quantities
- Algebraic Expressions and Identities
- Visualising Solid Shapes
- Mensuration
- Exponents and Powers
- Direct and Inverse Proportions
- Factorisation
- Introduction to Graphs
- Playing with Numbers
NCERT Solutions Class 8 Mathematics Solutions for Exercise 4.4 in Chapter 4 - Practical Geometry
Construct the following quadrilaterals,
(i) Quadrilateral DEAR
DE = 4 cm
EA = 5 cm
AR = 4.5 cm
\begin{array}{l} \angle \mathrm{E}=60^{\circ} \\ \angle \mathrm{A}=90^{\circ} \end{array}
(ii) Quadrilateral TRUE
TR = 3.5 cm
RU = 3 cm
UE = 4 cm
\begin{array}{l} \angle \mathrm{R}=75^{\circ} \\ \angle \mathrm{U}=120^{\circ} \end{array}
(i) Rough Figure:
(1) Draw a line segment DE of 4 cm and an angle of 60^{\circ} at point E. As vertex A is 5 cm away from vertex E, cut a line segment EA of 5 cm from this ray.
(2) Again draw an angle of 90^{\circ} at point A. As vertex R is 4.5 cm away from vertex A, cut a line segment RA of 4.5 cm from this ray.
(3) Join D to R.
(ii) Rough Figure:
(1) Draw a line segment RU of 3 cm and an angle of 120^{\circ} at point U. As vertex E is 4 cm away from vertex U, cut a line segment UE of 4 cm from this ray.
(2) Next, draw an angle of 75^{\circ} at point R. As vertex T is 3.5 cm away from vertex R, cut a line segment RT of 3.5 cm from this ray.
(3) Join T to E.
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