- Rational Numbers
- Linear Equations in One Variable
- Understanding Quadrilaterals
- Practical Geometry
- Data Handling
- Squares and Square Roots
- Cubes and Cube Roots
- Comparing Quantities
- Algebraic Expressions and Identities
- Visualising Solid Shapes
- Mensuration
- Exponents and Powers
- Direct and Inverse Proportions
- Factorisation
- Introduction to Graphs
- Playing with Numbers
NCERT Solutions Class 8 Mathematics Solutions for Exercise 4.1 in Chapter 4 - Practical Geometry
Construct the following quadrilaterals.
(i) Quadrilateral ABCD
AB = 4.5 cm
BC = 5.5 cm
CD = 4 cm
AD = 6 cm
AC = 7 cm
(ii) Quadrilateral JUMP
JU = 3.5 cm
UM = 4 cm
MP = 5 cm
PJ = 4.5 cm
PU = 6.5 cm
(iii)Parallelogram MORE
OR = 6 cm
RE = 4.5 cm
EO = 7.5 cm
(iv)Rhombus BEST
BE = 4.5 cm
ET = 6 cm
(i) The rough sketch of the quadrilateral ABCD can be drawn as follows.
(1) ΔABC can be constructed by using the given measurements as follows.
(2) Vertex D is 6 cm away from vertex A. Therefore, while taking A as centre, draw an arc of radius 6 cm.
(3) Taking C as centre, draw an arc of radius 4 cm, cutting the previous arc at point D. Joint D to A and C.
(ii) The rough sketch of the quadrilateral JUMP can be drawn as follows.
(1) Δ JUP can be constructed by using the given measurements as follows.
(2) Vertex M is 5 cm away from vertex P and 4 cm away from vertex U. Taking P and U as centres, draw arcs of radii 5 cm and 4 cm respectively. Let the point of intersection be M.
(3) Join M to P and U.
(iii) We know that opposite sides of a parallelogram are equal in length and also these are parallel to each other.
i.e., ME = OR, MO = ER
The rough sketch of the parallelogram MORE can be drawn as follows.
(1) Δ EOR can be constructed by using the given measurements as follows.
(2) Vertex M is 4.5 cm away from vertex O and 6 cm away from vertex E. Therefore, while taking O and E as centres, draw arcs of 4.5 cm radius and 6 cm radius respectively. These will intersect each other at point M.
(3) Join M to O and E.
(iv) We know that all sides of a rhombus are of the same measure. Hence, BE = ES = ST = TB
The rough sketch of the rhombus BEST can be drawn as follows.
(1) Δ BET can be constructed by using the given measurements as follows.
(2) Vertex S is 4.5 cm away from vertex E and also from vertex T. Therefore, while taking E and T as centres, draw arcs of 4.5 cm radius, which will be intersecting each other at point S.
(3) Join S to E and T.
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