# NCERT Solutions Class 8 Mathematics Solutions for Exercise 4.1 in Chapter 4 - Practical Geometry

Question 1 Exercise 4.1

AB = 4.5 cm

BC = 5.5 cm

CD = 4 cm

AC = 7 cm

JU = 3.5 cm

UM = 4 cm

MP = 5 cm

PJ = 4.5 cm

PU = 6.5 cm

(iii)Parallelogram MORE

OR = 6 cm

RE = 4.5 cm

EO = 7.5 cm

(iv)Rhombus BEST

BE = 4.5 cm

ET = 6 cm

(i) The rough sketch of the quadrilateral ABCD can be drawn as follows.

(1) ΔABC can be constructed by using the given measurements as follows.

(2) Vertex D is 6 cm away from vertex A. Therefore, while taking A as centre, draw an arc of radius 6 cm.

(3) Taking C as centre, draw an arc of radius 4 cm, cutting the previous arc at point D. Joint D to A and C.

(ii) The rough sketch of the quadrilateral JUMP can be drawn as follows.

(1) Δ JUP can be constructed by using the given measurements as follows.

(2) Vertex M is 5 cm away from vertex P and 4 cm away from vertex U. Taking P and U as centres, draw arcs of radii 5 cm and 4 cm respectively. Let the point of intersection be M.

(3) Join M to P and U.

(iii) We know that opposite sides of a parallelogram are equal in length and also these are parallel to each other.

i.e., ME = OR, MO = ER

The rough sketch of the parallelogram MORE can be drawn as follows.

(1) Δ EOR can be constructed by using the given measurements as follows.

(2) Vertex M is 4.5 cm away from vertex O and 6 cm away from vertex E. Therefore, while taking O and E as centres, draw arcs of 4.5 cm radius and 6 cm radius respectively. These will intersect each other at point M.

(3) Join M to O and E.

(iv) We know that all sides of a rhombus are of the same measure. Hence, BE = ES = ST = TB

The rough sketch of the rhombus BEST can be drawn as follows.

(1) Δ BET can be constructed by using the given measurements as follows.

(2) Vertex S is 4.5 cm away from vertex E and also from vertex T. Therefore, while taking E and T as centres, draw arcs of 4.5 cm radius, which will be intersecting each other at point S.

(3) Join S to E and T.

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