Jump to

- Rational Numbers
- Linear Equations in One Variable
- Understanding Quadrilaterals
- Practical Geometry
- Data Handling
- Squares and Square Roots
- Cubes and Cube Roots
- Comparing Quantities
- Algebraic Expressions and Identities
- Visualising Solid Shapes
- Mensuration
- Exponents and Powers
- Direct and Inverse Proportions
- Factorisation
- Introduction to Graphs
- Playing with Numbers

Q9) A grandfather is ten times older than his granddaughter. He is also 54 years older than her. Find their present ages.

Answer:

Solution:

Let the present age of granddaughter be x years.

Therefore, Grandfather’s age = 10x years.

According to question, 10x=x+54

\Rightarrow10x-x=54

\Rightarrow9x=54

\Rightarrow x=\frac{54}{9}=6 years.

Hence, granddaughter’s age = 6 years and grandfather’s age = 10 x 6 = 60 years.

hi kids our today's question says
a grandfather is 10 times older than his
Granddaughter
he is also 54 years older than her
find their present age okay so now
again
in all word problems like these we are
going to assign
variables to the different ages given
so firstly I Can say okay the
granddaughter so let
granddaughters age
px
so if the granddaughter's age is x
i know that my grandfather is 10 times
older than
her so naturally the grandfather's age
become 10x now
it is also a given that he is also
54 years older than her
so I Can say that x
plus 54
plus 54 gives me
10x on solving this
I get 9x is equal to 54
and finally, I can write x is equal to 54
by nine
that is six
so I know that x is six so that means
that my granddaughter
is six years old and
if my granddaughter is six years old my
grandfather is
10x which is 6
into 10 60 years old
so I can finally conclude that the grand
daughter
is 6 years old and the
Grandfather
is 60 years old

Related Questions

Was This helpful?

Chapters

Lido

Courses

Quick Links

Terms & Policies

Terms & Policies

2022 © Quality Tutorials Pvt Ltd All rights reserved