  Ncert solutions

Q11) Baichung’s father is 26 years younger than Baichung’s grandfather and 29 years older than Baichung. The sum of the ages of all the three is 135 years. What is the age of each one of them?

Solution:

Let Baichung’s age be x years, then Baichung’s father’s age = (x+29)

years and Baichung’s granddaughter’s age = (x+29+26)=(x+55) years.

According to condition, x+x+29+x+55=135

\Rightarrow\ 3x+84=135\ \Rightarrow3x+84-84=135-84

[Subtracting 84 from both sides]

\Rightarrow\ 3x=51\ \Rightarrow\ \frac{3x}{3}=\frac{51}{3}

[Dividing both sides by 3]

x = 17 years.

Hence, Baichung’s age = 17 years, Baichung’s father’s age = 17 + 29

= 46 years

And Baichung’s granddaughter’s age

= 17 + 29 + 26 = 72 years.

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