Ncert solutions

Ncert solutions

Ncert solutions

Grade 8

Q11) Baichung’s father is 26 years younger than Baichung’s grandfather and 29 years older than Baichung. The sum of the ages of all the three is 135 years. What is the age of each one of them?

Solution:

Let Baichung’s age be x years, then Baichung’s father’s age = (x+29)

years and Baichung’s granddaughter’s age = (x+29+26)=(x+55) years.

According to condition, x+x+29+x+55=135

\Rightarrow\ 3x+84=135\ \Rightarrow3x+84-84=135-84

[Subtracting 84 from both sides]

\Rightarrow\ 3x=51\ \Rightarrow\ \frac{3x}{3}=\frac{51}{3}

[Dividing both sides by 3]

x = 17 years.

Hence, Baichung’s age = 17 years, Baichung’s father’s age = 17 + 29

= 46 years

And Baichung’s granddaughter’s age

= 17 + 29 + 26 = 72 years.

Still have questions? Our expert teachers can help you out

Book a free class nowSolution:

Let Baichung’s age be x years, then Baichung’s father’s age = (x+29)

years and Baichung’s granddaughter’s age = (x+29+26)=(x+55) years.

According to condition, x+x+29+x+55=135

\Rightarrow\ 3x+84=135\ \Rightarrow3x+84-84=135-84

[Subtracting 84 from both sides]

\Rightarrow\ 3x=51\ \Rightarrow\ \frac{3x}{3}=\frac{51}{3}

[Dividing both sides by 3]

x = 17 years.

Hence, Baichung’s age = 17 years, Baichung’s father’s age = 17 + 29

= 46 years

And Baichung’s granddaughter’s age

= 17 + 29 + 26 = 72 years.

Still have questions? Our expert teachers can help you out

Book a free class nowLido

Courses

Race To Space

Quick Links

Terms & Policies

Terms & Policies