Ncert solutions

Ncert solutions

Grade 8

Linear Equations in One Variable | Exercise 2.2

Question 11

Q11) Baichung’s father is 26 years younger than Baichung’s grandfather and 29 years older than Baichung. The sum of the ages of all the three is 135 years. What is the age of each one of them?

Solution:

Let Baichung’s age be x years, then Baichung’s father’s age = (x+29)

years and Baichung’s granddaughter’s age = (x+29+26)=(x+55) years.

According to condition, x+x+29+x+55=135

\Rightarrow\ 3x+84=135\ \Rightarrow3x+84-84=135-84

[Subtracting 84 from both sides]

\Rightarrow\ 3x=51\ \Rightarrow\ \frac{3x}{3}=\frac{51}{3}

[Dividing both sides by 3]

x = 17 years.

Hence, Baichung’s age = 17 years, Baichung’s father’s age = 17 + 29

= 46 years

And Baichung’s granddaughter’s age

= 17 + 29 + 26 = 72 years.

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subject-cta

Question 11

Q11) Baichung’s father is 26 years younger than Baichung’s grandfather and 29 years older than Baichung. The sum of the ages of all the three is 135 years. What is the age of each one of them?

Solution:

Let Baichung’s age be x years, then Baichung’s father’s age = (x+29)

years and Baichung’s granddaughter’s age = (x+29+26)=(x+55) years.

According to condition, x+x+29+x+55=135

\Rightarrow\ 3x+84=135\ \Rightarrow3x+84-84=135-84

[Subtracting 84 from both sides]

\Rightarrow\ 3x=51\ \Rightarrow\ \frac{3x}{3}=\frac{51}{3}

[Dividing both sides by 3]

x = 17 years.

Hence, Baichung’s age = 17 years, Baichung’s father’s age = 17 + 29

= 46 years

And Baichung’s granddaughter’s age

= 17 + 29 + 26 = 72 years.

Still have questions? Our expert teachers can help you out

Book a free class now

Want to top your mathematics exam ?

Learn from an expert tutor.

Book a free class now
subject-cta
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