Ncert solutions

Ncert solutions

Grade 8

Linear Equations in One Variable | Exercise 2.2

Question 1

Q1) If you subtract \frac{1}{2} from a number and multiply the result by \frac{1}{2}, you get \frac{1}{8}. What is the number?

Solution:

Let the number be x

According to the question,

\frac{1}{2}\left(x-\frac{1}{2}\right)=\frac{1}{8}

\Rightarrow\ 2\times\frac{1}{2}\left(x-\frac{1}{1}\right)=\frac{1}{8}\times2

[Multiplying both sides by 2]

\Rightarrow\ x\ -\ \frac{1}{2}=\frac{1}{4}

\Rightarrow\ x-\frac{1}{2}+\frac{1}{2}=\frac{1}{4}+\frac{1}{2}

[Adding both sides \frac{1}{2}]

\Rightarrow\ x=\ \frac{1+2}{4}

\Rightarrow\ x\ =\ \frac{3}{4}

Hence, the required number is \frac{3}{4}

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subject-cta

Question 1

Q1) If you subtract \frac{1}{2} from a number and multiply the result by \frac{1}{2}, you get \frac{1}{8}. What is the number?

Solution:

Let the number be x

According to the question,

\frac{1}{2}\left(x-\frac{1}{2}\right)=\frac{1}{8}

\Rightarrow\ 2\times\frac{1}{2}\left(x-\frac{1}{1}\right)=\frac{1}{8}\times2

[Multiplying both sides by 2]

\Rightarrow\ x\ -\ \frac{1}{2}=\frac{1}{4}

\Rightarrow\ x-\frac{1}{2}+\frac{1}{2}=\frac{1}{4}+\frac{1}{2}

[Adding both sides \frac{1}{2}]

\Rightarrow\ x=\ \frac{1+2}{4}

\Rightarrow\ x\ =\ \frac{3}{4}

Hence, the required number is \frac{3}{4}

Still have questions? Our expert teachers can help you out

Book a free class now

Want to top your mathematics exam ?

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Book a free class now
subject-cta
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