\frac{3}{4 x+3}=\frac{1}{4 x}
Solution:
\begin{aligned} &\mathrm{LHS}=\frac{3}{4 \mathrm{x}+3} \neq \frac{1}{4 \mathrm{x}}\\ &\text { The correct statement is } \frac{a}{4 x+3}=\frac{a}{4 x+3} \end{aligned}
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