\frac{3 x^{2}+1}{3 x^{2}}=1+1=2
Solution:
\begin{aligned} &\mathrm{LHS}=\frac{3 x^{2}+1}{3 x^{2}}=\frac{3 x^{2}}{3 x^{2}}+\frac{1}{3 x^{2}}=1+\frac{1}{3 x^{2}} \neq 2=\mathrm{RHS}\\ &\text { The correct statement is } \frac{3 x^{2}+1}{3 x^{2}}=1+\frac{1}{3 x^{2}} \end{aligned}
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