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NCERT Solutions Class 8 Mathematics Solutions for Exercise 14.4 in Chapter 14 - Factorisation
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(a-4)(a-2)=a^{2}-8
Answer:
Solution:
\begin{aligned} &\mathrm{LHS}=(\mathrm{a}-4)(\mathrm{a}-2)=\mathrm{a}(\mathrm{a}-2)-4(\mathrm{a}-2)\\ &=a^{2}-2 a-4 a+8\\ &=a^{2}-6 a+8\\ &\neq a^{2}-8=R H S\\ &\text { The correct statement is }(a-4)(a-2)=a^{2}-6 a+8 \end{aligned}
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