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NCERT Solutions Class 8 Mathematics Solutions for Exercise 14.4 in Chapter 14 - Factorisation
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(2 a+3 b)(a-b)=2 a^{2}-3 b^{2}
Answer:
Solution:
\begin{array}{l} \mathrm{LHS}=(2 \mathrm{a}+3 \mathrm{b})(\mathrm{a}-\mathrm{b})=2 \mathrm{a}(\mathrm{a}-\mathrm{b})+3 \mathrm{b}(\mathrm{a}-\mathrm{b}) \\ =2 \mathrm{a}^{2}-2 \mathrm{ab}+3 \mathrm{ab}-3 \mathrm{b}^{2} \\ =2 \mathrm{a}^{2}+\mathrm{ab}-3 \mathrm{b}^{2} \\ \neq 2 \mathrm{a}^{2}-3 \mathrm{b}^{2}=\mathrm{RHS} \end{array}
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