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NCERT Solutions Class 8 Mathematics Solutions for Exercise 14.4 in Chapter 14 - Factorisation
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(y-3)^{2}=y^{2}-9
Answer:
Solution:
\begin{aligned} &\mathrm{LHS}=(\mathrm{y}-3)^{2}, \text { which is similar to }(\mathrm{a}-\mathrm{b})^{2} \text { identity, where }(\mathrm{a}-\mathrm{b})^{2}=\mathrm{a}^{2}+\mathrm{b}^{2}-2 \mathrm{ab}\\ &(y-3)^{2}=y^{2}+(3)^{2}-2 y \times 3=y^{2}+9-6 y \neq y^{2}-9=R H S\\ &\text { The correct statement is }(y-3)^{2}=y^{2}+9-6 y \end{aligned}
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