# NCERT Solutions Class 8 Mathematics Solutions for Exercise 14.4 in Chapter 14 - Factorisation

Question 1 Exercise 14.4

Q1) Find and correct the errors in the following mathematical statements.

a) 4(x-5)=4x-5

b) x\left(3x+2\right)=3x^2+2

c) 2x+3y=5xy

d) x+2x+3x=5x

e) 5y+2y+y-7y=0

f) 3x+2x=5x^2

g) \left(2x\right)^2+4\left(2x\right)+7=2x^2=8x+7

h) \left(2x\right)^2+5x=4x+5x=9x

i) \left(3x+2\right)^2+3x^2+6x+4

Solution 1:

a) 4(x-5)=4x-5

Correction=

4\left(x-5\right)\ne4x-5

4\left(x-5\right)=\ 4x-20

b) x\left(3x+2\right)=3x^2+2

Correction= x\left(3x+2\right)\ne3x^2+3y

x\left(3x+2\right)=3^2+2x

c) 2x+3y=5xy

Correction= x\left(3x+2\right)\ne3x^2+2x

2x+3y=2x+3y

d) x+2x+3x=5x

Correction= x+2x+3x\ne5x

x+2x+3x=6x

e) 5y+2y+y-7y=0

Correction= 5y+2y+y-7y\ne0

5y+2y+y-7y=8y-7y

f) 3x+2x=5x^2

Correction=

3x+2x\ne5x^2

3x+2x=5x

g) \left(2x\right)^2+4\left(2x\right)+7=2x^2=8x+7

Correction= \left(2x\right)^2+4\left(2x\right)+7=2x^2+8x+7

\left(2x\right)^2+4\left(2x\right)+7=4x^2+8x+7

h) \left(2x\right)^2+5x=4x+5x=9x

Correction= 2x^2+5x\ne4x+5x

\left(2x\right)^2+5x=4x^2+5x

i) \left(3x+2\right)^2+3x^2+6x+4

Correction: \left(3x+2\right)^2+3x^2+6x+4

\left(3x+2\right)^2+9x^2+12x+4

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