Jump to

- Rational Numbers
- Linear Equations in One Variable
- Understanding Quadrilaterals
- Practical Geometry
- Data Handling
- Squares and Square Roots
- Cubes and Cube Roots
- Comparing Quantities
- Algebraic Expressions and Identities
- Visualising Solid Shapes
- Mensuration
- Exponents and Powers
- Direct and Inverse Proportions
- Factorisation
- Introduction to Graphs
- Playing with Numbers

Question 16 Exercise 14.3

Factorize the expressions and divide them as directed:

39 y^{3}\left(50 y^{2}-98\right) \div 26 y^{2}(5 y+7)

Answer:

Solution:

Factorization is the process of breaking down one object (such as a number, matrix, or polynomial) into a product of another object, or factors, which when multiplied together produce the original object.

\begin{aligned} &\text { First solve for } 50 y^{2}-98, \text { we have }\\ &50 y^{2}-98=2\left(25 y^{2}-49\right)=2\left((5 y)^{2}-7^{2}\right)=2(5 y-7)(5 y+7)\\ &\text { Now, } 39 y^{3}\left(50 y^{2}-98\right) \div 26 y^{2}(5 y+7)=\frac{3 \times 13 \times y^{8} \times 2(5 y-7)(5 y+7)}{2 \times 13 \times y^{2}(5 y+7)}=3 y(5 y-7) \end{aligned}

"hello students i am rita your math
leader tutor and the today's question is
factorize the expressions and divide
them as directed
and the question is 39 y raised to power
3
bracket 50 y square minus
98 divided by 26
y raised to the power 2 bracket
5 y plus 7
first of all in this question we take
out common 2
from the 50 y square and 98 we take out
common
2 from them then we got 25 y
square minus 49
divided by 26 y
square five y plus seven
now 25 is the perfect
square of five and
25 is the perfect square of
5 and 49 is a perfect square of
7 so we can write it as 7 square
divided by 26 y raised to power 2
5 5 plus 7 now as we know
the formula of e square minus b square
is equal to a plus b bracket
a minus b now we use this identity
and solve the equation so 39
into 2 y raised to power 3
into a plus b 5 y plus
7 into 5 5 minus
7 divided by 26
y raised to power 2 bracket 5
y plus 7 now we cancel out the terms
5 y plus seven and
thirteen twos are thirteen threes are
and two ones are two ones are
so we got the answer and the answer is
3 and y is to power 3 and y is to power
2 so 3 minus 2 we got 1 so single y
y is 2 power 1 bracket 5 y
minus 7 so this is our answer i hope you
like this video so please subscribe leo
for more updates and do comment your
questions thank you"

Related Questions

Was This helpful?

Chapters

Lido

Courses

Quick Links

Terms & Policies

Terms & Policies

2022 © Quality Tutorials Pvt Ltd All rights reserved