NCERT Solutions Class 8 Mathematics Solutions for Exercise 14.3 in Chapter 14 - Factorisation

Question 12 Exercise 14.3

Factorize the expressions and divide them as directed:

4 y z\left(z^{2}+6 z-16\right) \div 2 y(z+8)



A polynomial that is referred to as "quadratic" is expressed as "ax2 + bx + c," where "a," "b," and "c" are simple numbers. We can determine the two integers that will add up to equal "b," the coefficient on the x-term, in addition to multiplying to equal the product term "ac" for factorization purposes.

\begin{array}{l} \text { Factorize } z^{2}+6 z-16 \\ z^{2}+6 z-16=z^{2}-2 z+8 z-16=(z-2)(z+8) \\ \text { Now, } 4 y z\left(z^{2}+6 z-16\right) \div 2 y(z+8)=4 y z(z-2)(z+8) / 2 y(z+8=2 z(z-2) \end{array}

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